Find the number of five digit positive integers divisible by 3 that can be formed using the digits 0, 1, 2, 3, 4 and 5, without repeating any of the digits.
216
The number of five digit numbers that can be formed using 0, 1, 2, 3, 4, 5 which will be divisible by 3 is = 5! + 5! – 4! = 216