Find the number of five digit positive integers divisible by 3 that can be formed using the digits 0, 1, 2, 3, 4 and 5, without repeating any of the digits.

216

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240

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120

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186

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Solution

The correct option is A
216

The number of five digit numbers that can be formed using 0, 1, 2, 3, 4, 5 which will be divisible by 3 is = 5! + 5! – 4! = 216

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