Find the number of formula units of $F e S O_{4} .7 H_{2} O$ present in 11 millimoles of $F e S O_{4} .7 H_{2} O$ .

0.011 N_{A}

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0.11 N_{A}

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1.1 N_{A}

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11 N_{A}

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Solution

The correct option is A $0.011 N_{A}$
Number of formula units $= n u m b e r o f m o l e s \times N_{A} f o r m u l a u n i t s / m o l$
$11 m i l l i m o l e s = 11 \times 10^{- 3} m o l e s o r 0.011 m o l e s$
Number of formula units $= 0.011 \times N_{A}$

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Similar questions

Find the number of formula units of $F e S O_{4} .7 H_{2} O$ present in 11 millimoles of $F e S O_{4} .7 H_{2} O$ .

Q. Calculate the number of

F e S O_{4} . 7 H_{2} O

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0.2

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F e S O_{4} . 7 H_{2} O

Q. Calculate the number of

F e S O_{4} . 7 H_{2} O

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Q. If we have a

F e S O_{4} .7 H_{2} O

sample and it contains a total of 2233 oxygen atoms, then find the number of formula units of

F e S O_{4} .7 H_{2} O

present in the sample.

If the total number of electrons present in a pure sample of $F e S O_{4} . 7 H_{2} O$ is $4.336 \times 10^{26}$
then the total number of moles of oxygen atoms present in $F e S O_{4} .7 H_{2} O$ :

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Find the number of formula units of FeSO4.7H2O present in 11 millimoles of FeSO4.7H2O.

The correct option is A 0.011NANumber of formula units =number of moles×NAformula units/mol 11 millimoles=11×10−3moles or 0.011moles Number of formula units =0.011×NA

Find the number of formula units of $F e S O_{4} .7 H_{2} O$ present in 11 millimoles of $F e S O_{4} .7 H_{2} O$ .

The correct option is A $0.011 N_{A}$
Number of formula units $= n u m b e r o f m o l e s \times N_{A} f o r m u l a u n i t s / m o l$
$11 m i l l i m o l e s = 11 \times 10^{- 3} m o l e s o r 0.011 m o l e s$
Number of formula units $= 0.011 \times N_{A}$