CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the number of free electrons per unit volume of a metallic wire of density 104 kg/m3 and atomic mass number 100. The number of free electrons per atom is one.

A
6.022×1023
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
6.022×1025
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
6.022×1028
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
6.022×1030
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 6.022×1028
We know that, number of mole,

n=MassAtomic mass=Number of atomAvogadro Number

104×1100×103=x6.022×1023 [ρ=mV]

x=6.022×1028

As number of free electrons per atom is 1, so, number of free electrons will be 6.022×1028.

flag
Suggest Corrections
thumbs-up
40
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon