Question

Find the number of in which 10 different flowers can be strung to form a garland so that 3 particular flowers are always together.

• A. 30240
• B. 30420
• C. 23400
• D. none of (a), (b), (c)

Answer 1

The correct option is A 30240

Since 3 particulars flowers are together.
Hence there can be total (10 - 3) + 1 = 8 flowers. These 8 flowers can be arranged 7! ways but the 3 flowers which are together can be arranged mutually in 3! ways.
Hence, the required number of ways = 3! $\times$ 7!
$=6\times 5040=30240$