Question

Find the number of integers in the domain of $\sqrt{5-x^2}$

• A. 2
• B. 3
• C. 4
• D. 5

Answer 1

The correct option is D

5

(x) = $\sqrt{5-x^2}$

For f(x) to be defined,

5 - $x^2$ $\ge$ 0

$x^2$ $\le$ 5

$\Rightarrow$ x $\in$ $(-\sqrt{-5},\sqrt{5})$

{-2 ,-1,0,1,2} $\in$ $(-\sqrt{-5},\sqrt{5})$

$\Rightarrow$ Numbr of integers in the domain of f(x) is 5.