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Question

Find the number of integral terms in the expansion of (3+85)256

A
33
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B
34
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C
35
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D
32
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Solution

The correct option is A 33
(31/2+51/8)256

Tr+1=256Cr(3)256r5r8

For integral terms 256r2,r8 are both positive integer
r=0,8,16,....256
256=0+(n1)8 using tn=a+(n1)d

2568=n1

n=2568+1
n=32+1=33

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