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Byju's Answer
Standard XII
Mathematics
Logarithmic Inequalities
Find the numb...
Question
Find the number of integral values of
a
so that the inequation
x
2
−
2
(
a
+
1
)
x
+
3
(
a
−
3
)
(
a
+
1
)
<
0
is satisfied by atleast one
x
∈
R
+
.
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Solution
x
2
−
2
(
a
+
1
)
x
+
3
(
a
−
3
)
(
a
+
1
)
<
0
This inequality holds when
(
a
+
1
)
2
−
3
(
a
−
3
)
(
a
+
1
)
<
0
⟹
(
a
+
1
)
(
a
−
4
)
>
0
a
∈
(
−
∞
,
−
1
)
∪
(
4
,
∞
)
Infinite no of integral values are there
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Q.
The number of integral value(s) of x satisfying the inequality
√
x
−
1
x
−
2
≤
0
is