Find the number of integral values of K for which the equation 7cosx+5sinx=2k+1 has at least one solution.
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Solution
−√a2+b2≤asinx+bcosx≤√a2+b2∴−√74≤7cosx+5sinx≤√74⇒−√74≤2k+1≤√74 Since k is integer −9<2k+1<9⇒−10<k<8⇒−5<k<4 Hnece number of possible integer values of k=8