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Oxyacids of Phosphorus

Find the numb...

Question

Find the number of ions formed on dissolving one molecule of FeSO $_{4}$ (NH $_{4}$ ) $_{2}$ SO $_{4}$ .6H $_{2}$ O in water :

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Solution

The correct option is D 5
It is a double salt :
FeSO $_{4}$ (NH $_{4}$ ) $_{2}$ SO $_{4}$ .6H $_{2}$ O $⟶$ Fe $^{2 +}$ + 2SO $_{4}^{2 -}$ + 2NH $_{4}^{+}$ + 6 $H_{2} O$
So the number of ions formed are 5.
Hence option D is correct.

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