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Chelation

Find the numb...

Question

Find the number of ligand(s) which is/are non-classical ligand.
$C O, N O, C_{2} H_{4}, C$ $_{3}$ H $_{5}^{-}$ , $H^{-}$

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Solution

The number of ligand(s) which is/are non-classical ligand is 4. These include CO, NO, C $_{2}$ H $_{4}$ , C $_{3}$ H $_{5}^{-}$ .
They are pi bonding ligands.
They form complexes only with transition metals by simultaneous donor and acceptor interaction between occupied and free orbitals of the pi ligand and the d orbitals of the metal.

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\begin{matrix} List-I & List-II (C o m p o u n d s) (I) [P t (N O_{2})_{2} (e n)_{2}]^{2 +} & (P) Stable according to EAN-Rule (I I) [C r (π - C_{6} H_{6}) (N O)_{2}] & (Q) Both ligands act as ambidentate (I I I) [I r (S C N) (S O_{4}) (N H_{3})_{4}] & (R) Bond order M - L bond > 1.0 (I V) [V (C_{2} H_{4}) (C N)_{5}] & (S) Bond order of Ligands decrease (T) C o - o r d i n a t i o n n u m b e r o f c e n t r a l m e t a l i s s i x \end{matrix}

\begin{matrix} List-I & List-II (C o m p o u n d s) (I) [P t (N O_{2})_{2} (e n)_{2}]^{2 +} & (P) Stable according to EAN-Rule (I I) [C r (π - C_{6} H_{6}) (N O)_{2}] & (Q) Both ligands acts as ambidentate (I I I) [I r (S C N) (S O_{4}) (N H_{3})_{4}] & (R) Bond order M - L bond > 1.0 (I V) [V (C_{2} H_{4}) (C N)_{5}] & (S) B o n d o r d e r o f L i g a n d s d e c r e a s e s (T) C o - o r d i n a t i o n n u m b e r o f c e n t r a l m e t a l i s s i x \end{matrix}

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