Find the number of lines of symmetry in the following shapes.

(a)-1, (b)-1, (c)-1

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(a)-2, (b)-1, (c)-3

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(a)-3, (b)-2, (c)-1

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(a)-1, (b)-3, (c)-2

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Solution

The correct option is A (a)-1, (b)-1, (c)-1
The imaginary line along which you can fold the figure to get completely overlapping halves is called a line of symmetry of the figure.
The lines of symmetry for the figures are shown below.

It can be seen that the christmas tree, butterfly and the arrow all have only one line of symmetry.

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Similar questions

∣ ∣ ∣ ∣ ∣ \begin{matrix} 1 + a^{2} + a^{4} & 1 + a b + a^{2} b^{2} & 1 + a c + a^{2} c^{2} 1 + a b + a^{2} b^{2} & 1 + b^{2} + b^{4} & 1 + b c + b^{2} c^{2} 1 + a c + a^{2} c^{2} & 1 + b c + b^{2} c^{2} & 1 + c^{2} + c^{4} \end{matrix} ∣ ∣ ∣ ∣ ∣ = {(a - b)}^{2} {(b - c)}^{2} {(c - a)}^{2}

a, b, c

\frac{(1 + a + a^{2}) (1 + b + b^{2}) (1 + c + c^{2})}{a b c}

a b + b c + c a = 1

\frac{a}{1 + a^{2}} + \frac{b}{1 + b^{2}} + \frac{c}{1 + c^{2}}

\frac{2}{\sqrt{(1 + a^{2}) (1 + b^{2}) (1 + c^{2})}}

A B C sin 2 A + sin 2 B + sin 2 C = 4 sin A sin B sin C

a + b + c = 2

a^{2} + b^{2} + c^{2} = 1

a b c = 3

\frac{1}{a} + \frac{1}{b} + \frac{1}{c}

1 + b + b^{2} + . . . + b^{2} + . . . . + b^{n} = (1 + b) (1 + b^{2}) (1 + b^{4}) (1 + b^{8})

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