Find the number of molecule (s) having octahedral geometry from the following :
$S_{2} F_{10}, X e O_{6}^{4 -}, P C l_{6}^{-}, [S i F_{6}]^{2}, S e F_{6}, T e F_{6}, S F_{6}, P O_{4}^{3 -}$

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Solution

Molecule which is $s p^{3} d^{2}$ hybridised has octahedral shape.
In $S_{2} F_{10}$ , central atom is $s p^{3} d^{2}$ hybridised
In $X e O_{6}^{4 -}$ is $s p^{3} d^{2}$ hybridised
In $P C l_{6}^{-}$ is $s p^{3} d^{2}$ hybridised
In $[S F_{6}]^{2}$ is $s p^{3} d^{2}$ hybridised
In $S e F_{6}$ is $s p^{3} d^{2}$ hybridised
In $T e F_{6}$ is $s p^{3} d^{2}$ hybridised
In $S F_{6}$ is $s p^{3} d^{2}$ hybridised
But $P O_{4}^{3 -}$ is is $s p^{3}$ hybridised
So, total 7 molecules have octahedral shape.

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