Find the number of molecule(s) which do not exist
$N C l_{3}, P C l_{3}, P C l_{5}, N C l_{5}, P F_{2}, O F_{4}, O F_{6}$

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Solution

Out of $N C l_{3}, P C l_{3}, P C l_{5}, N C l_{5}, P F_{2}, O F_{4}, O F_{6}$ molecules, $N C l_{5}, P F_{2}, O F_{4}, O F_{6}$ molecules do not exist.

$N C l_{5}$ does not exist because N does not have d orbitals and hence can not form 5 hybridization orbitals to form $P C l_{5}$ .

$P F_{2}$ cannot exist because P can have a valency of 3 or 5 only.
$O F_{4}$ and $O F_{6}$ cannot exist because oxygen cannot have a covalency of 4 or 6.

So total number of molecules do not exist are 4.

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