Find the number of molecules in 1.8 g of $H_{2} O$

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Solution

1 mol of $H_{2} O$ = Avogadro's number of molecules of $H_{2} O$ = $6.023 \times 10^{23} m o l e c u l e s o f w a t e r$
Also, 1 mol of $H_{2} O$ = Molecular mass of $H_{2} O$
i.e. Molecular mass of $H_{2} O$ = $6.023 \times 10^{23} m o l e c u l e s o f w a t e r$
Molecular mass of water = $(2 \times M a s s o f h y d r o g e n + M a s s o f o x y g e n)$
= $(2 \times 1 + 16)$
= 18 g
$\Rightarrow$ $18 g of H_{2} O = 6.022 \times 10^{23}$ molecules of water
So, 1.8 g of $H_{2} O$ = $\frac{6.022}{18} \times 1.8$ molecules of water
1.8 g of $H_{2} O$ = $6.02 \times 10^{22} m o l e c u l e s o f w a t e r$

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Find the number of molecules in 1.8 g of H2O

Find the number of molecules in 1.8 g of $H_{2} O$