Question

Find the number of moles and the number of H atoms present in $9.033\times {10}^{23}$ molecules of water.

• A. 3 moles
• B. $18.066\times {10}^{23}$ atoms
• C. 6 moles
• D. $9.033\times {10}^{23}$ atoms

Answer 1

Answer: (A), (B)

$18.066\times {10}^{23}$ atoms

The chemical formula of water is $H_{2}O$.

One molecule of water has 2 hydrogen atoms.

$9.033\times {10}^{23}$ molecules of water will have $18.066\times {10}^{23}$ atoms of hydrogen.

We know that,
number of moles = $\frac{Numberofparticles/atoms}{Avogadr{o}^{\prime }sno.}$
= $\frac{18.066\times {10}^{23}}{6.022\times {10}^{23}}$
= $3moles$