Find the number of moles of CaSO 4- 2 H 2 O present in 3-011 - 1024 formula units of CaSO 4- 2 H 2 OA- 10B- 5C- 1D- 15

The correct option is B 5Number of nbsp; moles = number of formula units/Avogadro number =3.011× 10^24/6.022×10^23 =5 moles ...

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Mole Concept

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Question

Find the number of moles of $C a S O_{4} .2 H_{2} O$ present in $3.011 \times 10^{24}$ formula units of $C a S O_{4} .2 H_{2} O$

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Similar questions

H_{2} S O_{4}

C a (O H)_{2} .

C a S O_{4}

H_{2} S O_{4} + C a (O H)_{2} \to C a S O_{4} + 2 H_{2} O

C a S O_{4}

C a S O_{4} .

$C a S O_{4} .2 H_{2} O Δ 120^{\circ} C - ----- \to A - - + 3 H_{2} O . A$ is

C a S O_{4} \cdot 2 H_{2} O

C a S O_{4} \cdot \frac{1}{2} H_{2} O

C a S O_{4} \cdot 2 H_{2} O (s) \to C a S O_{4} \cdot \frac{1}{2} H_{2} O (s) + \frac{3}{2} H_{2} O (g)

Δ_{f} H^{⊖}

C a S O_{4} \cdot 2 H_{2} O (s), C a S O_{4} \frac{1}{2} H_{2} O (s), H_{2} O (g)

- 2021.0 k J m o l^{- 1}

- 1575.0 k J m o l^{- 1}

- 241.8 k J m o l^{- 1}

194.0

130.0

188.0 J K^{- 1} m o l^{- 1} .

R = 8.314 J K^{- 1} m o l^{- 1} = 0.0831 L b a r m o l^{- 1} K^{- 1}

1 K g

C a S O_{4} \cdot 2 H_{2} O (s)

^{- 1}

C a S O_{4} \cdot \frac{1}{2} H_{2} O (s)

C a S O_{4}

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