Question

Find the number of moles of 'X' atoms in $93$ g. of 'X'. [X is phosphorus $=31$].

Answer 1

No. of moles of $x$ atoms in $93g$ of $x$

$x$ is phosphorous

Given Mass=$93g$

Gram atomic Mass=$31g$

No. of moles$=\frac{Givenmass}{GramAtomicMass}=\frac{93}{31}=3$

The no. of moles of $x$ atoms is $3$moles