Clearly the numbers between 250 and 1000 which are divisible by 3 are 252,255,258,...999.
∴Tn=999=a+[n−1]d
999=252+[n−1]3
333=84+n−1
∴n=333−83=250
Find the sum of all natural numbers between 250 and 1000 which are exactly divisible by 3.