Question

Find the number of non-polar and non-planar species among the following:
(i) $S{O}_3$ (ii) $PC{l}_3{F}_2$ (iii) $P_4$
(iv) $N{H}_3$ (v) $C{O}_2$ (vi) $C{F}_4$
(vii) $B{F}_3$ (viiii) $SiC{l}_4$ (ix) $HCl{O}_4$
(x) $S{F}_4$

• A. 4
• B. 5
• C. 8
• D. 6

Answer 1

The correct option is A 4

(i) $S{O}_3$- Trigonal planar and non-polar.
(ii) $PC{l}_3{F}_2$- Trigonal bipyramidal and non-polar.
(iii) $P_4$- Trigonal pyramidal and non-polar.
(iv) $N{H}_3$- Trigonal pyramidal and polar.
(v) $C{O}_2$- Linear and non-polar.
(vi) $C{F}_4$- Tetrahedral and non-polar.
(vii) $B{F}_3$- Trigonal planar and non-polar.
(viiii) $SiC{l}_4$- Tetrahedral and non-polar.
(ix) $HCl{O}_4$- Tetrahedral and polar.
(x) $S{F}_4$- See-saw and polar.

Thus, the non-polar and non-planar species are $PC{l}_3{F}_2,P_4,C{F}_4,SiC{l}_4$. Hence, 4 compounds are non-polar and non-planar.