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B
4.014×1020
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C
8.029×1023
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D
8.029×1020
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Solution
The correct option is C8.029×1023 1 mole of NO2 contains 2 moles of O-atoms. So, 23 moles of NO2 will contain 43 moles of O-atoms. Again, 1 mole of O-atoms = 6.022×1023 O-atoms Therefore, 43 moles of O-atoms =43×6.022×1023 =8.029×1023 O-atoms