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Question

Find the number of polynomials of the form x3+ax2+bx+c that are divisible by x2+1, where a, b, c ϵ{1,2,3,...,9,10}.

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Solution

x+a
x2+1)¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯x3+ax2+bx+c
x3+x
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ax2+(b1)x+c
ax2+a
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯(b1)x+ca
Now, remainder (b1)x+ca must be zero for any x. Then, b1=0 and ca=0
b=1 and c=a
Now, c or a can be selected in 10 ways. Hence, the number of polynomials are 10.

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