Find the number of polynomials of the form x3+ax2+bx+c that are divisible by x2+1, where a, b, c ϵ{1,2,3,...,9,10}.
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Solution
x+a x2+1)¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯x3+ax2+bx+c x3+x ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ax2+(b−1)x+c ax2+a ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯(b−1)x+c−a Now, remainder (b−1)x+c−a must be zero for any x. Then, b−1=0 and c−a=0 ⇒b=1 and c=a Now, c or a can be selected in 10 ways. Hence, the number of polynomials are 10.