Find the number of rational roots of
$P (x) = 2 x^{98} + 3 x^{97} + 2 x^{96} + . . . . . + 2 x + 3 = 0$

2

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $2$
$P (x) = 2 x^{98} + 3 x^{97} + 2 x^{96} + . . . . . + 2 x + 3 = 0$
Carrying out the $2 x + 3$ and $x + 1$ as common term
$(2 x + 3) (x^{97} + x^{96} + . . . .1) = (2 x + 3) (x + 1) (x^{96} + x^{94} + . . . .1)$
Hecne two rational roots are $x = \frac{- 3}{2}, - 1$

Suggest Corrections

Similar questions

2 x^{99} + 3 x^{98} + 2 x^{97} + . . . + 2 x + 3 = 0

| x^{2} - 2 x - 3 | + 4 x = 0

{2 x}^{4} + x^{3} - {11 x}^{2} + x + 2 = 0

2 x^{4} + x^{3} - 11 x^{2} + x + 2 = 0

2 x^{100} + 5 x^{99} + 2 x^{98} + . . . . + 2 x + 5 = 0

98

a x^{2} + b x + c = 0

D = b^{2} - 4 a c

Join BYJU'S Learning Program