Find the number of real roots in the equation , $4 x^{2} + 3 x + 5 = 0$

0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $0$
$Δ \geq 0$ for real roots .
$b^{2} - 4 a c$
$= 9 - (80)$
$- 71 < 0$ $∴$
it has no real roots.

Suggest Corrections

Similar questions

x^{2} - 3 x + 5 = 0

4 x^{2} + 3 x + 5 = 0

λ

(x^{2} + 3 x + 5)^{2} - (λ - 3) (x^{2} + 3 x + 4) (x^{2} + 3 x + 5) + (λ - 4) (x^{2} + 3 x + 4)^{2} = 0

4 x^{2} - 3 x - 1 = 0

4 x^{2} + 3 x + 5 = 0

Join BYJU'S Learning Program