Find the number of real roots of the equation $2^{2} x^{2} - 7 x + 5 = 1$ .

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Solution

Solution:-
$2^{2} x^{2} - 7 x + 5 = 1 {G i v e n}$
$4 x^{2} - 7 x + 5 - 1 = 0$
$\Rightarrow 4 x^{2} - 7 x + 4 = 0$
$∴ D = b^{2} - 4 a c = {(- 7)}^{2} - 4 \times 4 \times 4$
$= 49 - 64 = - 15$
Since $D < 0$ , there will be no real roots.
Hence the correct answer is 0.

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