⟹ Total number of letters =10
ee––– x–– p– r– ss––– i– o– n––
Double letters bundles =2
Single letters =6+2=8 ( 1-e, 1-s)
Possible ways of selection include:-
All 4 from single =8C4=70
2 from single 1 from double =7C2×2C1=42
2 from double =2C2=1
Total Selections =113
Number of arrangements:-
All from single =8C4×4!=1680
2 from single 1 from double =7C2×2C1×4!2!=504
2 from double =2C2×4!2!2!=6
Total =2190