Question

Find the number of sides in a regular polygon if each interior angle is eight times the adjacent exterior angle

Answer 1

The sum of exterior angle and its adjacent interior is ${180}^0$, that is,

$e+i={180}^0$

Since each interior angle is eight times the adjacent exterior angle, therefore, substitute $i=8e$.

$e+8e={180}^0\Rightarrow 9e={180}^0\Rightarrow e=\frac{{180}^0}{9}={20}^0$

We know that the measure of exterior angle is $e={\left(\frac{360}{n}\right)}^0$ where $n$ is the number of sides.

Here, it is given that the exterior angle is $e={20}^0$, therefore,

$n=\frac{360}{e}=\frac{360}{20}=18$

Hence, the number of sides is $18$.