Question

Find the number of sides of a regular polygon if each exterior angle measures: ${40}^o$

Answer 1

We know that the measure of exterior angle is $x={\left(\frac{360}{n}\right)}^0$ where $n$ is the number of sides.

Here, it is given that the exterior angle is $x={40}^0$, therefore,

$n=\frac{360}{x}=\frac{360}{40}=9$

Hence, the number of sides is $9$.