Question

Find the number of sides of a regular polygon if each exterior angle measures: ${72}^o$

Answer 1

We know that the measure of exterior angle of a resular polygon is ${\left(\frac{360}{n}\right)}^0$ where $n$ is the number of sides.

Here, it is given that the exterior angle is ${72}^0$, therefore,

$n=\frac{{360}^o}{{72}^o}=5$

Hence, the required number of sides are $5$.