wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the number of six digit odd numbers that are greater than 60000 and can be formed with the digits 5,6,7,8,9,0 when repetition is not allowed.

A
150
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
120
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
480
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
240
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 240
5,6,7,8,9,0
Numbers greater than 60000
Case: 1 First position is 6 Other 4 places by (5,7,9)
3×4×3×2=72
Case: 2 First position is 7 Other 4 places by (5,9)
2×4×3×2=48
Case: 3 First position is 8 Other 4 places by (5,7,9)
3×4×3×2=72
Case: 4 First position is 9 Other 4 places by (5,7,9)
2×4×3×2=48
Total possible numbers =72+48+72+48=240

869648_596172_ans_04e98524ae6a4252a61c6e5b91a15889.png

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Permutations
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon