CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the number of six digit odd numbers that are greater than 60000 and can be formed with the digits 5,6,7,8,9,0 when repetition of digits is allowed?

A
12440
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
12500
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
15552
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
25100
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is D 15552
We need find 6 digit odd numbers greater than 600000 using 5,6,7,8,9,0
The first digit can be any of the 6 except 0,5.
Since number should be greater than 600000.
The last digit must be either 5,7 or 9 since it should be odd. The 4 digits in the middle can be filled with any of the six given numbers.
Total =4×6×6×6×6×3
=15552

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Permutations
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon