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Question

Find the number of solution for the equation sin2x+sin4x=2sin3x between the interval 0xπ

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Solution

Given, sin2x+sin4x=2sin3x
2sin3xcosx=2sin3x
sin3xcosxsin3x=0
sin3x(cosx1)=0
sin3x=0 or cosx=0
x=nπ3 or x=2nπ

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