Question

Find the number of solution(s) of $\sqrt{2}y+\frac{x}{\sqrt[3]{35}}=3\sqrt{3}$ for $x=45.$

• A. One.
• B. Two.
• C. Infinitely Many.
• D. This is not a linear equation.

Answer 1

The correct option is A One.

The given equation is a linear equation with two variables as the exponent of the variables is 1.
$\sqrt{2}y+\frac{x}{\sqrt[3]{35}}=3\sqrt{3}$
$\Rightarrow \sqrt{2}{y}^1+\frac{x^1}{\sqrt[3]{35}}=3\sqrt{3}$

Hence, for a given value of $x,$
$y$ has a corresponding value, i.e., one solution.
$\Rightarrow \sqrt{2}y+\frac{45}{\sqrt[3]{35}}=3\sqrt{3}$
$\Rightarrow \sqrt{2}y=3\sqrt{3}-\frac{45}{\sqrt[3]{35}}$
$\Rightarrow y=\frac{3\sqrt{3}-\frac{45}{\sqrt[3]{35}}}{\sqrt{2}}$