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Question

Find the number of solutions of the equations;

2cosx=|sinx| when xϵ[2π,2π]

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Solution

We have 2cosα=|sinx|

It is true only for |sinx|=1sinx=±1

x=2nπ±π2

x[2π,2π]

x=π2,π2,3π2,3π2

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