wiz-icon
MyQuestionIcon
MyQuestionIcon
13
You visited us 13 times! Enjoying our articles? Unlock Full Access!
Question

Find the number of terms in the following AP: 18,312,13,...47


A

34,27

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

26,35

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

27,34

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

35,26

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A

34,27


Given AP is

18,312,13,...47

First term, a=18

Common difference, d=31218=52

an =−47

Using formula an=a+(n1)d to find nth term of arithmetic progression, we get

47=18+(n1)[52]

94=365n+5

5n=135
n=1355=27

Therefore, there are 27 terms in the given arithmetic progression.


flag
Suggest Corrections
thumbs-up
30
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
nth Term of an AP
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon