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Question

Find the number of terms in the following AP: 18,312,13,...47


A

34,27

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B

26,35

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C

27,34

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D

35,26

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Solution

The correct option is A

34,27


Given AP is

18,312,13,...47

First term, a=18

Common difference, d=31218=52

an =−47

Using formula an=a+(n1)d to find nth term of arithmetic progression, we get

47=18+(n1)[52]

94=365n+5

5n=135
n=1355=27

Therefore, there are 27 terms in the given arithmetic progression.


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