CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question

Find the number of terms of the given AP:
7,13,19....,205


A

34,27

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

26,35

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

27,34

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

35,26

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B

34,27


Formula to find nth term of arithmetic progression is

tn=a1+(n1)d

where,

'a1' is the first term,

'd' is the common difference,

'n' is the number of terms,

'tn' is the nth term.

Given, a1=7 , a2=13, tn=205

d = a2 - a1 = 13 - 7 = 6

Substituting the values in the formula tn=a+(n1)d to find nth term of arithmetic progression, we get

205=7+(n1)6
205=6n+1

204=6n

n=2046=34

Therefore, there are 34 terms in the given arithmetic progression.


flag
Suggest Corrections
thumbs-up
7
BNAT
mid-banner-image