Find the number of terms in expansion of ${(1 + 2 x + x^{2})}^{20}$ .

39

No worries! We‘ve got your back. Try BYJU‘S free classes today!

40

No worries! We‘ve got your back. Try BYJU‘S free classes today!

41

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

42

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $41$
$(1 + 2 x + x^{2})^{20} = [(x + 1)^{2}]^{20} = (x + 1) 40$
$∴$ Number of terms $= 40 + 1 = 41$

Suggest Corrections

Similar questions

The number of terms in the expansion (1+2x+x²)²⁰ are.

(1 + 2 x + x^{2})^{20}

{(1 + 2 x + x^{2})}^{20}

{(1 + 2 x + x^{2})}^{20}

39, 42, 47, 38, 42, 40, 42, 38, 43, 42, 38, 44, 46, 39, 42, 40, 43, 42, 41

Join BYJU'S Learning Program