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Question

Find the number of terms in the expansion of (a+b+c)n.

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Solution

A is the correct choice. We have (a+b+c)n=[a+(b+c)]n

=an+nC1an1(b+c)1+nC2an2(b+c)2+.....+nCn(b+c)n

Further, expanding each term of R.H.S., we note that

First term consist of 1 term.

Second term on simplification gives 2 terms.

Third term on expansion gives 3 terms.

Similarly, fourth term on expansion gives 4 terms and so on.

The total number of terms =1+2+2+3+....+(n+1)=(n+1)(n+2)2.


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