Find the number of terms in the expansion of (a+b+c)n.
A is the correct choice. We have (a+b+c)n=[a+(b+c)]n
=an+nC1an−1(b+c)1+nC2an−2(b+c)2+.....+nCn(b+c)n
Further, expanding each term of R.H.S., we note that
First term consist of 1 term.
Second term on simplification gives 2 terms.
Third term on expansion gives 3 terms.
Similarly, fourth term on expansion gives 4 terms and so on.
The total number of terms =1+2+2+3+....+(n+1)=(n+1)(n+2)2.