1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XII
Mathematics
Multinomial Expansion
Find the numb...
Question
Find the number of terms in the expansion of
(
2
x
+
3
y
+
z
)
7
.
Open in App
Solution
Fact: Number of dissimilar terms in the expansion of
(
x
1
+
x
2
+
x
3
+
.
.
.
.
.
.
+
x
r
)
n
is
n
+
r
−
1
C
n
So in
(
2
x
+
3
y
+
z
)
7
, we have
r
=
3
and
n
=
7
Thus number of terms in the expansion of
(
2
x
+
3
y
+
z
)
7
is
7
+
3
−
1
C
7
=
9
C
7
=
36
Suggest Corrections
0
Similar questions
Q.
The sum of all coefficients in expansion of
(
2
x
−
3
y
+
z
)
7
Q.
The number of terms in the expansion of
[
(
x
−
3
y
)
2
(
x
+
3
y
)
2
]
3
is
Q.
Find the number of terms in the expansions of the following
(
2
x
−
3
y
)
9
Q.
Write the number of terms in the expansion of
2
x
+
y
3
4
7
.
Q.
Find the middle term in the expansion of
(
2
x
+
3
y
)
8
.
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Beyond Binomials
MATHEMATICS
Watch in App
Explore more
AP Board
Multinomial Expansion
Standard XII Mathematics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app