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Question

Find the number of terms in the expansion of (49+68)500 which are integers.

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Solution

General term Tr+1 =500Cr(31/2)500r(21/2)r =500Cr3250r/2.2r/2
For r=0,2,4,6,8,10,12,.....500,
Powers of 3 and 2 are integers.
Hence, the integers terms =251
Alternative:
(91/4+81/6)500
=(31/2+21/2)500
Now, the total number of integral terms will be
1+500L.C.M(2,2)
=1+5002
=1+250
=251

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