Find the number of terms in the expansion of (x1+x2+x3....xk)n
(x1+x2+x3......xk)n=∑r1+r2+r3...rk=nn!r1!+r2!×...rk!×xr11xr22....xrkk
Total numbers of terms in this expansion in this expansion is equal to the number of non-negative solution of r1+r2+...rk=n
=n+k−1Ck−1
=n+k−1Cn