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Question

Find the number of terms in the expression obtained after adding the expressions
4x22yz+3x3 and 2zy+x2+y3

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Solution

(4x22yz+3x3)+(2zy+x2+y3)
=9x22yz+3x3+2zy+x2+y3
Grouping the like terms together,
we get
=(9x2+x2)+(2+2)yz+3x3+y3
=x2(9+1)+0yz+3x3+y3
=10x2+3x3+y3

Number of terms = 3

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