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Question

Find the number of terms in the series 20, 1913, 1823 ........ of which the sum is 300 ?

A
only 25 terms
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B
only 36 terms
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C
only 49 terms
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D
none of these
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Solution

The correct options are
A only 25 terms
B only 36 terms
20,1913,1823........

191320

=58320=58603=23

again

18231913


=563583=23

191320=18231913=23=d

the given series is a A.P where first term a=20

a=20,23

Let the read.no. pf terms be n

Sn=300

n2[2a+(n1)d]=300

n2[2×20+(n1)×23]=300

n[20+(13)(n1)]=300

n[2013(n1)]=300

[60n+1]=900

n[61n]=900

n261n+900=0

n236n25n+900=0

n(n36)25(n36)=0

n=25 or n=36

both option A and B.

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