Question

Find the number of terms of a G.P. whose first term is $\frac{3}{4}$, common ratio is 2 and the last term is 384.

Answer 1

Formula,

$a_n=a{r}^{n-1}$

Given,

$384=\left(\frac{3}{4}\right)2^{n-1}$

$\frac{384\times 4}{3}=2^{n-1}$

$512=2^{n-1}$

$2^9=2^{n-1}$

$9=n-1$

$\therefore n=10$

The number of terms are 10.