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Question

Find the number of terms of the AP 54,51,48,. So that their sum is 513.

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Solution

Formula:

Sn=n2[2a+(n1)d]

Given,

513=n2[2(54)+(n1)(3)]

1026=n[1083n+3]

3n2111n+1026=0

(n19)(n18)=0

n=19,18

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