Find the number of terms of the series 32, 24, 16, 8 ... for which the sum of the terms is zero.

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Solution

The correct option is D 6
Soln:
S_n = [2a + (n -1) d]
0 = [64 – (n – 1)8]
n (72 – 8n) = 0
n = 9
So, number of terms required is 9. Hence (e)

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