Find the number of three digit natural numbers which are divisible by 11
The series of three-digit numbers which are divisible by 11 : 110,121,132,.........990
The above series is an AP, in which
First term, a=110
Common difference, d=11
Last term, L=990
We know that the nth term of an AP is given by
an=a+(n−1)d
⇒a+(n−1)d=990 [ Let nth term is 990]
⇒110+(n−1)×11=990
⇒11×(n−1)=990−110
⇒11(n−1)=880
⇒n−1=80
⇒n=81
Hence, there are 81 three-digit numbers which are divisible by 11.