Find the number of times intensity is maximum in time interval of $1 s e c$ .

4

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Solution

The correct option is A $4$
$f_{1} = \frac{100 π}{2 π} = 50 H z$

$f_{2} = \frac{92 π}{2 π} = 46 H z$
Number of times intensity of maximum in time interval of $1 s e c .$
$N = (f_{1} - f_{2}) . 1 s e c = (50 - 40) .1 s e c = 4$

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