Find the number of trees that can be planted in a triangular ground having sides $51 m, 37 m$ and $20 m$ , when each tree occupies $6 m^{2}$ of space:

54

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51

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82

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43

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Solution

The correct option is A $51$
Area of $△ = \sqrt{s (s - a) (s - b) (s - c)}, s = \frac{a + b + c}{2} = \frac{51 + 37 + 20}{2} = 54 m$

$∴$ Area of triangle ground $= \sqrt{54 (54 - 51) (54 - 37) (54 - 20)}$

$= \sqrt{54 \times 3 \times 17 \times 34} = 306 m^{2}$
Number of trees $= \frac{306}{6} = 51$

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Find the number of trees that can be planted in a triangular ground having sides 51m,37m and 20m, when each tree occupies 6m2 of space:

The correct option is A 51Area of △=√s(s−a)(s−b)(s−c),s=a+b+c2=51+37+202=54m∴ Area of triangle ground =√54(54−51)(54−37)(54−20) =√54×3×17×34=306m2 Number of trees =3066=51

Find the number of trees that can be planted in a triangular ground having sides $51 m, 37 m$ and $20 m$ , when each tree occupies $6 m^{2}$ of space: