Find the number of unpaired electrons in the $t_{2 g}$ set of $d$ -orbitals of $[M n (H_{2} O)_{6}]^{2 +}$

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Solution

In $[M n (H_{2} O)_{6}]^{2 +}$ , $M n^{2 +}$ has $d^{5}$ configuration. As water is weak field ligand, crystal field splitting energy is less than pairing energy. So pairing does not occur. There are $3$ unpaired electrons in $t_{2 g}$ and $2$ unpaired electrons in $e_{g}$ orbital.

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